6x^2-32x=24

Solution for 6x^2-32x=24 equation:

6x^2-32x=24

We move all terms to the left:

6x^2-32x-(24)=0

a = 6; b = -32; c = -24;
Δ = b2-4ac
Δ = -322-4·6·(-24)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-40}{2*6}=\frac{-8}{12}
=-2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+40}{2*6}=\frac{72}{12}
=6
$